Question

see the picture​ no 39

Answer 1

Answer:

Ans - 39

Step-by-step explanation:

Let the two digit number be 10y+x

it is given that 10y+x=4(x+y)...(1)

and 10y+x=3xy...(2)

So, 10y+x=4x+4y and

⇒63y=3x

⇒2y=x

Substituting in (2)

10y+2y=6y2

⇒12y=6y2

⇒2=y

⇒x=4

∴ The number is 10×2+4=24

Hope it is helpful

thank you

Answer 2

Step-by-step explanation:

$⇒ \bold\pink{given} = a \: the \: two \: digit \: number \: is four \: \\ times \: the \: sum \: and \: three \: times \\ the \: product \: of \: its \: digit . \\ \bold\red{to \: find \: } = what \: is \: the \: number.. \\ \\ </p><p>$

⇒let 2 numbers = 10y+x

⇒10y +x=4(y+x)

⇒10y +x=4y+4x

⇒10y-4y=4x-x

⇒6y=3x

$⇒x = \frac{6y}{3} \\ ⇒x = 2y..(i)$

also 10y+x=3xy....(ii)

⇒10y+2y=3(2y)(y)

⇒12y=6y²

⇒6y²-12xy=0

⇒6y(y-2) =0

Thus:- y=0 (or) 2..

in (i) x=2y

⇒2(2)

⇒4..

Thus:- 10y+x

:-10(2) +4

:-20+4

:-24...is the correct answer..