Question

See the Pictures and please answer correctly ​

Answer 1

Answer:

$the \: time \: period \: for \: simple \: pandulum \: is \: given \: by \: the \: equation$

$t = 2\pi \sqrt{1 \g} </p><p>From this we get </p><p></p><p>[tex]g = 4\ {\pi}^{2} \frac{1}{ {t}^{2} }$

So the error associated with the acceleration given by :

$\frac{△g}{g} = \frac{△1}{1} + 2 \times \frac{△t}{t}$

Substituting the value ,

$\frac{△g}{g} \% = ( \frac{0.1}{20} ) +( 2 \times \frac{1}{90} \times 100$

$0.027 \times 100\%$

$= 2.7\%$

I hope it will help you