Question

see the question above and answer it​

Answer 1

Answer:

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Answer 2

Answer:

LCM of 10 and 15 is 30

so we equalise dinominator by multiplying

and we get,

27/30 and 32/30

But we get only 5 rationals no. between them

So now,

after 30, 60 is the no. which is common in 10 and 15

so we multiplying 2 in both nominator and dinominator in both the no.

and we get

54/60 and 64/60

therefore, the required 10 rationals no. are between 54/60 and 64/60