Question

see this attachment and answer ​

Answer 1

Given :-

A force 10 N acts on a block af mass 10 kg at an angle of 60° displaces it 5 metre. (cos 60° = ½)

To Find :-

What is the work.

Formula Used :-

${\red{\boxed{\large{\bold{Work\: Done\: =\: Fs\: Cos\theta}}}}}$

where,

F = Force

s = Displacement

$\thetaθ$ = Angle between applied force and displacement.

Solution :-

Given :

Force = 10 N

Displacement = 5 m

According to the question by using the formula we get,

⇒ $\sf Work\: Done$=$\: Fs\:Cos$

( As we know that, $Cos\theta =\: \dfrac{1}{2}θ=$

⇒ $\sf Work\: Done =\: {\cancel{10}} \times 5 \times \dfrac{1}{\cancel{2}}$

⇒ $\sf Work\: Done =\: 5 \times$

➠ $\sf\bold{\purple{Work\: Done =\: 25\: J}}$

$\therefore$ The work done is 25 J .

Answer 2

$\boxed{W = F.d.cos θ}$

Where,

→ F is the force applied

→ d is the displacement

→ θ is the angle between force and direction of motion

W = 10N × 5m × cos 60⁰

W = 10N × 5m × 1/2

W = 25 Nm or 25 J