Math, asked by todayishugday, 1 month ago

see this attachment and answer it ​

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Answered by OounicornloveroO
3

Answer:

Given:-

Force = 10 N

mass = 10 kg

Angle = 60⁰

displacement = 5 m

Cos60⁰ =

2

1

To find:-

Work done

Formula to be used:-

\longrightarrow⟶ done = Force × displacement × CosØ}}

workdone=Force×displacement×CosØ

Solution:-

implies⟹ done = 10 × 5 × Workdone=10×5×

2

1

implies⟹ done = 5 × 5workdone=5×5

implies⟹ done = 25 Joulesworkdone=25Joules

Answered by Anonymous
107

Gɪᴠᴇɴ ⤵

A ғᴏʀᴄᴇ 10 N ᴀᴄᴛs ᴏɴ ᴀ ʙʟᴏᴄᴋ ᴀғ ᴍᴀss 10 ᴋɢ ᴀᴛ ᴀɴ ᴀɴɢʟᴇ ᴏғ 60° ᴅɪsᴘʟᴀᴄᴇs ɪᴛ 5 ᴍᴇᴛʀᴇ. (ᴄᴏs 60° = ½)

Tᴏ Fɪɴᴅ ⤵

Wʜᴀᴛ ɪs ᴛʜᴇ ᴡᴏʀᴋ.

Fᴏʀᴍᴜʟᴀ Usᴇᴅ ⤵

{\red{\boxed{\large{\bold{Work\: Done\: =\: Fs\: Cos\theta}}}}}

ᴡʜᴇʀᴇ⤵

↦F = Fᴏʀᴄᴇ

↦s = Dɪsᴘʟᴀᴄᴇᴍᴇɴᴛ

Sᴏʟᴜᴛɪᴏɴ :-

Gɪᴠᴇɴ :⤵

↦Fᴏʀᴄᴇ = 10 N

↦Dɪsᴘʟᴀᴄᴇᴍᴇɴᴛ = 5 ᴍ

Aᴄᴄᴏʀᴅɪɴɢ ᴛᴏ ᴛʜᴇ Qᴜᴇsᴛɪᴏɴ ʙʏ ᴜsɪɴɢ ᴛʜᴇ ғᴏʀᴍᴜʟᴀ ᴡᴇ ɢᴇᴛ,

\sf Work\: DoneWork \: Done =\:Fs\:Cos\ \: =FsCosθ

( As we know that, Cos\theta =\: \dfrac{1}{2}θ=

⇒ \sf Work\: Done =\: {\cancel{10}} \times 5 \times \dfrac{1}{\cancel{2}}

⇒ \sf Work\: Done =\: 5

➠ \sf\bold{\purple{Work\: Done =\: 25\: J}}

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