Question

see this pic..

A rectangular container is 50 cm long and 30 cm wide. It contains 7.5 L of water. What is
the height of the water level in the container?

I will follow you if you give me the right answer..

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Answer 1

Answer:

Step-by-step explanation:

Have Given :-

Length of container = 50 cm.

Width of container = 30 cm.

$∵ 1 L = 1 × {10}^{ - 3} \: m³$

$∴ 7.5 \: L = 75 \times {10}^{ - 4} \: m³$

Since the container holds 75 × 10^-4 m³ of water.

∴ Volume of rectangular container = l × b × h

$75 \times {10}^{ - 4} = 50 × 30 × h$

$75 \times {10}^{ - 4} = 1500 × h$

$\frac{75 \times {10}^{ - 4} }{15 \times {10}^{2} } = h$

$\frac{ \cancel{75} \times {10}^{ - 4} \times {10}^{2} }{ \cancel{15}} = h$

$\frac{5 \times {10}^{ - 4 + 2} }{1} = h$

$5 \times {10}^{ - 2} = h$

$0.05 \: m = h$

$or \: \: h = 0.05 \: m$

$h = 5 \: cm$

Therefore, the height of the water level will be 5 cm.

Answer 2

Answer:

Step-by-step explanation:

Have Given :-

Length of container = 50 cm.

Width of container = 30 cm.

$∵ 1 L = 1 × {10}^{ - 3} \: m³$

$∴ 7.5 \: L = 75 \times {10}^{ - 4} \: m³$

Since the container holds 75 × 10^-4 m³ of water.

∴ Volume of rectangular container = l × b × h

$75 \times {10}^{ - 4} = 50 × 30 × h$

$75 \times {10}^{ - 4} = 1500 × h$

$\frac{75 \times {10}^{ - 4} }{15 \times {10}^{2} } = h$

$\frac{ \cancel{75} \times {10}^{ - 4} \times {10}^{2} }{ \cancel{15}} = h$

$\frac{5 \times {10}^{ - 4 + 2} }{1} = h$

$5 \times {10}^{ - 2} = h$

$0.05 \: m = h$

$or \: \: h = 0.05 \: m$

$h = 5 \: cm$

Therefore, the height of the water level will be 5 cm.

Answer 3

Answer:

Step-by-step explanation:

Have Given :-

Length of container = 50 cm.

Width of container = 30 cm.

$∵ 1 L = 1 × {10}^{ - 3} \: m³$

$∴ 7.5 \: L = 75 \times {10}^{ - 4} \: m³$

Since the container holds 75 × 10^-4 m³ of water.

∴ Volume of rectangular container = l × b × h

$75 \times {10}^{ - 4} = 50 × 30 × h$

$75 \times {10}^{ - 4} = 1500 × h$

$\frac{75 \times {10}^{ - 4} }{15 \times {10}^{2} } = h$

$\frac{ \cancel{75} \times {10}^{ - 4} \times {10}^{2} }{ \cancel{15}} = h$

$\frac{5 \times {10}^{ - 4 + 2} }{1} = h$

$5 \times {10}^{ - 2} = h$

$0.05 \: m = h$

$or \: \: h = 0.05 \: m$

$h = 5 \: cm$

Therefore, the height of the water level will be 5 cm.

Answer 4

Answer:

Step-by-step explanation:

Have Given :-

Length of container = 50 cm.

Width of container = 30 cm.

$∵ 1 L = 1 × {10}^{ - 3} \: m³$

$∴ 7.5 \: L = 75 \times {10}^{ - 4} \: m³$

Since the container holds 75 × 10^-4 m³ of water.

∴ Volume of rectangular container = l × b × h

$75 \times {10}^{ - 4} = 50 × 30 × h$

$75 \times {10}^{ - 4} = 1500 × h$

$\frac{75 \times {10}^{ - 4} }{15 \times {10}^{2} } = h$

$\frac{ \cancel{75} \times {10}^{ - 4} \times {10}^{2} }{ \cancel{15}} = h$

$\frac{5 \times {10}^{ - 4 + 2} }{1} = h$

$5 \times {10}^{ - 2} = h$

$0.05 \: m = h$

$or \: \: h = 0.05 \: m$

$h = 5 \: cm$

Therefore, the height of the water level will be 5 cm.

Answer 5

Answer:

Step-by-step explanation:

Have Given :-

Length of container = 50 cm.

Width of container = 30 cm.

$∵ 1 L = 1 × {10}^{ - 3} \: m³$

$∴ 7.5 \: L = 75 \times {10}^{ - 4} \: m³$

Since the container holds 75 × 10^-4 m³ of water.

∴ Volume of rectangular container = l × b × h

$75 \times {10}^{ - 4} = 50 × 30 × h$

$75 \times {10}^{ - 4} = 1500 × h$

$\frac{75 \times {10}^{ - 4} }{15 \times {10}^{2} } = h$

$\frac{ \cancel{75} \times {10}^{ - 4} \times {10}^{2} }{ \cancel{15}} = h$

$\frac{5 \times {10}^{ - 4 + 2} }{1} = h$

$5 \times {10}^{ - 2} = h$

$0.05 \: m = h$

$or \: \: h = 0.05 \: m$

$h = 5 \: cm$

Therefore, the height of the water level will be 5 cm.

Answer 6

Answer:

Step-by-step explanation:

Have Given :-

Length of container = 50 cm.

Width of container = 30 cm.

$∵ 1 L = 1 × {10}^{ - 3} \: m³$

$∴ 7.5 \: L = 75 \times {10}^{ - 4} \: m³$

Since the container holds 75 × 10^-4 m³ of water.

∴ Volume of rectangular container = l × b × h

$75 \times {10}^{ - 4} = 50 × 30 × h$

$75 \times {10}^{ - 4} = 1500 × h$

$\frac{75 \times {10}^{ - 4} }{15 \times {10}^{2} } = h$

$\frac{ \cancel{75} \times {10}^{ - 4} \times {10}^{2} }{ \cancel{15}} = h$

$\frac{5 \times {10}^{ - 4 + 2} }{1} = h$

$5 \times {10}^{ - 2} = h$

$0.05 \: m = h$

$or \: \: h = 0.05 \: m$

$h = 5 \: cm$

Therefore, the height of the water level will be 5 cm.