Question

see this pic ......... answer now

jai siya ram_/\_

no spam​

Answer 1

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

given: ABCD is a parallelogram and AB = 10 cm; AD = 6 cm

AE is the angle bisector of angle A.

∠DAF=∠AFB [alternate interior angles]

∠DAF=∠FAB [since AE is the angle bisector of angle A]

⇒∠AFB=∠FAB

in the triangle AFB;

∠AFB=∠FAB⇒BF=AB=10cm

[since sides opposite to equal angles are equal]

BC = AD = 6 cm [opposite sides of a parallelogram are equal]

CF = BF - BC

= 10 - 6

= 4 cm

2.

Answer 2

Explanation:

$given \: parallelogram \: abcd \\ and \: ab = 6cm \\ bc = 5cm \\ac = 7cm \\ so \: by \: property \: of \: || gm \: \\ cd = 6cm \\ so \: distance = 12 - 7cm = 5cm$