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as e is mid point of ab ae=eb-----1
and as f is mid point of CD cf=df------2
given that ae=df------3
this implies from the above 3 relations that
ae=eb=df=cf
so ae+eb=df+cf
hence ab=cd
and as f is mid point of CD cf=df------2
given that ae=df------3
this implies from the above 3 relations that
ae=eb=df=cf
so ae+eb=df+cf
hence ab=cd
Ramlayaksingh3:
it's wrong bro
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