Math, asked by Ramlayaksingh3, 1 year ago

☆SEEKING CONTENT QUALITY ANSWERS☆
evaluate the question given in the attachment using
x + y + z = 0   \\  {x}^{3} +  {y}^{3}  + z ^{3}   = 3xyz
the final answer is 0.018 .answer it honestly. best answer will get the most brainiliest.

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Answers

Answered by vinay181
1
here is your answer under your conditions,

using identity:
x3 + y3 + z3  - 3xyz = (x + y + z)(x2 + y2 + z2 – xy – yz – zx)

if x + y + z = 0,
then, x3 + y3 + z3  - 3xyz = 0
or x3 + y3 + z3  = 3xyz

(0.2)3 - (0.3)3 + (0.1)3 can be written as (0.2)3+ (-0.3)3 + (0.1)3 
//since (-x)3 = -x3 //
here, (0.2) + (-0.3) + (0.1) = 0.3 - 0.3 = 0
so, (0.2)3 - (0.3)3 + (0.1)3 = 3*(0.2)(-0.3)(0.1) =
- 0.018
if this help plz mark this as brainliest.........:)
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