Question

seema and reena go for jogging .seema jogs for 2 1/5 km and reema 2 1/7 km. who jogs more and by how much?​

Answer 1

• seema = 2 1/5 = 11/5km
• reena = 2 1/7 = 15/7km

$subtract$

$= \frac{11}{5} - \frac{15}{7} \\ = \frac{77 - 75}{35} \\ = \frac{2}{35}$

Therefore, seema jog 2/35km more than reema.

Answer 2

• seema = 2 1/5 = 11/5km
• reena = 2 1/7 = 15/7km

$subtract$

$= \frac{11}{5} - \frac{15}{7} \\ = \frac{77 - 75}{35} \\ = \frac{2}{35}$

Therefore, seema jog 2/35km more than reema.

Answer 3

• seema = 2 1/5 = 11/5km
• reena = 2 1/7 = 15/7km

$subtract$

$= \frac{11}{5} - \frac{15}{7} \\ = \frac{77 - 75}{35} \\ = \frac{2}{35}$

Therefore, seema jog 2/35km more than reema.