Math, asked by vipinmamgai40, 1 year ago

seema borrowed rupees 10,000. at the end of 3 years seema had to pay rupees 13,600 on the bank. what was the rate of interest?

Answers

Answered by kartikpant94
20
principal(P) = 10000
time(T) = 3 years
amount = 13600
let rate of intrest=R
SI= P×R×T/100
SI= 10000×R×3/100
SI=300R
Amount = P+SI
13600=10000+300R
3600=300R
3600/300 = R
R = 12%
Rate of intrest = 12%
Answered by shivamcr7ii
15

Answer:


Step-by-step explanation:

Principal(P) = 10000

Time(T) = 3 years

Amount = 13600

Let rate of intrest=R

Simple interest (SI)= P×R×T/100

SI= 10000×R×3/100

SI=300R

Amount = P+SI

13600=10000+300R

3600=300R

3600/300 = R

R = 12%

Rate of intrest = 12%

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