Seema can walk 5 km in 1 hr 15 min. How far can she go in 30 min
Answers
Answer:
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Answer:
Step-by-step explanation:
Let normal speed of a student be x km/h
Distance (d) = 3 km
Time = distance/speed = 3/x hours
If a student had walk 1 km/h faster then his speed would have been x + 1 km/h.
Time = 3/(x+1)
begin mathsize 16px style 3 over straight x minus fraction numerator 3 over denominator straight x plus 1 end fraction equals 15 over 60
3 open parentheses 1 over straight x minus fraction numerator 1 over denominator straight x plus 1 end fraction close parentheses equals 1 fourth
12 open parentheses fraction numerator begin display style straight x plus 1 minus straight x end style over denominator begin display style straight x open parentheses straight x plus 1 close parentheses end style end fraction close parentheses equals 1
12 equals straight x squared space plus space straight x
straight x squared space plus space straight x space minus space 12 space equals space 0
left parenthesis straight x space plus space 4 right parenthesis left parenthesis straight x space minus space 3 right parenthesis space equals space 0
straight x space equals space minus 4 space or space straight x space equals space 3
straight x space not equal to negative 4 space hence space straight x space equals space 3 space km divided by hour
end style