Seema has 180 rupees int he form of 5 rupee coins and 2 rupee coins . the no. 2 rupee coins is 2 times that of 5 rupee coins . find the no. of coins of each denomination
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Let the number of 2 rupees coin be x and number of 5 rupees coin be y
Then u will get two equations :
x=2y......eq 1
And 2 x +5y =180........ eq2
Now
2x+5y=180
4y+5y=180.................from eq 1.
9y=180
y=20
x =20 ×2=40
No of 5 rupees coin =20 and number of 2 rupees coin is 40
Then u will get two equations :
x=2y......eq 1
And 2 x +5y =180........ eq2
Now
2x+5y=180
4y+5y=180.................from eq 1.
9y=180
y=20
x =20 ×2=40
No of 5 rupees coin =20 and number of 2 rupees coin is 40
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