Question

Seema has three balls A, B and C. A is
twice as heavy as B , B weights
one third of C , The
heaviest ball is
​

Answer 1

Answer:

Step-by-step explanation:

The heaviest weight of ball is B

A is twice heavy=2

So we do multiply 1/3×2=2/6

Now compare time

1/3 2/6

3×6>1×2

=18>2

Please make me as brainliest

Answer 2

Answer:

Seema has three balls A,B, and C.A is twice as heavy as B,B ... heavy as B, B weighs 1/3 of C.The heaviest ball is (i)A (ii)B (iii)C (iv)Can't ... The heaviest weight of ball is B.

Step-by-step explanation:

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