Question

Seema has three balls, A, B and C. A is twice as heavy as B, B weighs one-third of C. The heaviest
ball is
A
B
C
(iv) Can't determine​
make answer with full steps the answer is C plz make answer in c
scammers are not allowed to answer

Answer 1

Let’s say that B=x
Then, A should be (2times B) which is A=2x
If B is one-third of C then, C should be B*3, which is 3x
Comparing all the values,
A=2x
B=x
C=3x

Therefore C is the heaviest ball along all.