Question

seema is 3 year older then reema and veena is 5 years older then reema . if the sum of their ages is 29 year ,find their ages

Answer 1

Ages of Reema, Seema and Veena are 7,10 and 12 years respectively.

Given,

Seema is 3 year older then Reema and Veena is 5 years older then Reema.

To find,

If the sum of their ages is 29 year, find their ages.

Solution,

Let Reema's age be "x"

Seema's age = 3+x

Veena's age = 5+x

x + 3 + x + 5 + x = 29

3x + 8 = 29

3x = 29 - 8

3x = 21

x = 21/3

x = 7

Reema's age = x = 7 years

Seema's age = 3+x = 10 years

Veena's age = 5+x = 12 years

#SPJ3

Answer 2

Answer:

The present ages of the three girls are: reema = 7 years, seema = 10 years, veena = 12 years.

Step-by-step explanation:

As per the data given in the question,

Lets assume the age of reema as $x$ years.

so, age of seema will be $x+3$ years. (given)

and, age of veena will be $x+5$ years. (given)

∵ sum of their ages = 29 years

so, $x + (x+3) + (x+5) = 29$

$3x + 8 = 29$

$3x = 29-8$

$3x = 21$

$x=7$

∴ Age of reema will be= $x$ years = 7 years

∴ Age of seema will be= $x+3$ years= 10 years

∴ Age of veena will be= $x+5$ years = 12 years

#SPJ2