Question

Seema is 5 years older than her younger brother. After 9 years, the sum of their ages will be 53 years. Find their present ages.

Answer 1

EXPLANATION.

Seema is 5 years older than her younger brother.

after 9 years the sum of their age will be 53

.Find their present age.

Let the age of younger brother = x years.

Let the age of seema is = x + 5 years.

After 9 years the sum of their age is 53

=> x + 9 + x + 5 + 9 = 53

=> 2x + 23 = 53

=> 2x = 53 - 23

=> 2x = 30

=> x = 15

Therefore,

Present age of younger brother x = 15

years.present age of seema = x + 5 ; 15 + 5 = 20 years.

Answer 2

$\sf\huge\blue{\underline{\underline{ Question : }}}$

Seema is 5 years older than her younger brother. After 9 years, the sum of their ages will be 53 years. Find their present ages.

$\sf\huge\blue{\underline{\underline{ Solution : }}}$

★ Given that,

• Seema was 5 years older than her younger brother.
• After 9 years, the sum of their ages will be 53 years.

★ To find,

• Present ages of Seema and her brother.

★ Let,

$\bf\red{:\implies Age\:of\:Seema's\:brother= x \: years. }$

$\bf\red{:\implies Age\:of\:Seema= (x + 5)\;years.....(1) }$

★ According to the Question,

• Later 9 years, the sum of their ages = 53 years.

★ Now,

$\bf\:\implies (x + 9) + (x + 5 + 9) = 53$

$\bf\:\implies 2x + 23 = 53$

$\bf\:\implies 2x = 53 - 23$

$\bf\:\implies 2x = 30$

$\bf\:\implies { x = \frac{30}{2}}$

$\bf\:\implies x = 15$

➡ Since, present age of Seema's brother age = 15 years.

• Substitute value of x in (1)

$\bf\:\implies 15 + 5$

$\bf\:\implies 20$

$\underline{\boxed{\bf{\purple{ \therefore Present\:age\:of\:Seema = 20 \: years. }}}}\:\orange{\bigstar}$

$\underline{\boxed{\bf{\purple{ \therefore Present\:age\:of\:Seema's\:brother = 15\:years. }}}}\:\orange{\bigstar}$

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