Question

Seema is 5 years younger to her sister Reema. If the sum of their ages is 37 years, what are their present ages?​

Answer 1

Given that:

• Seema is 5 years younger to her sister Reema.
• Sum of their ages is 37 years.

Need to find:

• Their present ages = ?

Assumption:

• Let's Reema age be x years.
• Let's Seema age be (x-5) years.

According to the question —

$\sf \implies \: x + (x -5) = 37 \\ \\ \sf \implies \: 2x - 5 = 37 \\ \\ \sf \implies \: 2x = 37 + 5 \\ \\ \sf \implies \: 2x = 42 \\ \\ \sf \implies \: x = \cancel\frac{42}{2} \\ \\ \sf \implies \: x = 21$

Hence,the value of x is 21 years.

Therefore

• Present age of Reema = x = 21 years
• Present age of Seema = x-5 = 21-5 = 16 years