Seema is 9 year older then Been. in 10 year, Seema will be twice as old as been was 10 year ago. Find their present ages.
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Let the present age of seema = x.
Let the present age of Been = y.
Given that Seema is 9 year older than Been.
x = y + 9 ---- (1)
Given that In 10 year, Seema will be twice as old as Been was 10 years ago.
x + 10 = 2(y - 10) ----- (2)
Substitute (2) in (1), we get
y + 9 + 10 = 2y - 20
y + 19 = 2y - 20
2y - y = 20 + 19
y = 39.
Therefore the age of Been = 39 years.
The age of Seema = y + 9
= 39 + 9
= 48 years.
Hope this helps!
Let the present age of Been = y.
Given that Seema is 9 year older than Been.
x = y + 9 ---- (1)
Given that In 10 year, Seema will be twice as old as Been was 10 years ago.
x + 10 = 2(y - 10) ----- (2)
Substitute (2) in (1), we get
y + 9 + 10 = 2y - 20
y + 19 = 2y - 20
2y - y = 20 + 19
y = 39.
Therefore the age of Been = 39 years.
The age of Seema = y + 9
= 39 + 9
= 48 years.
Hope this helps!
siddhartharao77:
:-)
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