Question

Seema is 9 years old than Beema. After 10 years Seema will be twice as the age of Beema 10 years before. What are their present ages?

Answer 1

Seema is now 9 years older than beena.

in 10 years seema will be twice as old as beena was 10 years ago

Required: their present ages

Let the present age of beena be x then, present age of seema is x+9

therefore, after 10 years, seema will be twice as old as beena was 10 years ago

=> x+9+10 = 2(x - 10)

=> x+19 = 2x - 20

=> x = 19 +20

=> x = 39

seema's age = x+9 = 39 +9 = 48 years

Therefore, the present age of Beena is 39 years while the present age of Seema is 48 years

Answer 2

Hi,
Here is the answer to your query:-

Let age of BEEMA be x then age of SEEMA will be x+9
A. T. Q.
x+9+10=2(x-10)
x+19=2x-20
x-2x=-20-19
-x=-39
x=39
Age of BEEMA = 39 years.
Age of SEEMA = 39+9
= 48 years

Thanks.