Seema is half the
age
of her mother
Sangita . Find their ages after 4
years.
Answers
Answered by
1
Step-by-step explanation:
let the age of seema be 'x'
then her mother age becomes '2x'
After four years ages of,
seema=x+4
sangita=2x+4
Answered by
0
Answer:
Sangita age=x
her daughter age=1/2x
after four years their age will be
=4xand her daughter is half of his age then her age =2x
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