Seema is now 9 gears older than beena .in 10 years seema will be twice as old as beena was 10 years ago.find their percent ages.
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Answered by
12
let beena's age = x
seema's age = x+9
in 10 years seema's age will be twice beena's age
x+9+10 = 2x
19 = 2x-x
x = 19
therefore beena is 19 and
seema is 19+9=28
seema's age = x+9
in 10 years seema's age will be twice beena's age
x+9+10 = 2x
19 = 2x-x
x = 19
therefore beena is 19 and
seema is 19+9=28
Answered by
8
Let Seema's present age be S
Let Beena's present age be B
According to the question,
S = 9 + B ....(1)
S + 10 = 2( B - 10 )
S + 10 = 2B - 20
S = 2B - 30 ....(2)
Using equations (1) and (2), we have
B + 9 = 2B - 30
B = 39
S = 9 + B = 9 + 39 = 48
Therefore,
Present age of Seema = 48 years
Present age of Beena = 39 years
Let Beena's present age be B
According to the question,
S = 9 + B ....(1)
S + 10 = 2( B - 10 )
S + 10 = 2B - 20
S = 2B - 30 ....(2)
Using equations (1) and (2), we have
B + 9 = 2B - 30
B = 39
S = 9 + B = 9 + 39 = 48
Therefore,
Present age of Seema = 48 years
Present age of Beena = 39 years
Rhydima:
Thanx
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