Math, asked by ranjangyan7251, 1 month ago

seema is now 9 years older than beena. in 10 years seema will be twice as old as beena was 10 years ago find their present age

Answers

Answered by tennetiraj86
4

Step-by-step explanation:

Given :-

Seema is now 9 years older than Beena. in 10 years Seema will be twice as old as Beena was 10 years ago.

To find :-

Find their present age ?

Solution :-

Let the present age of Beena be X years

Then,

The present age of Seema

= 9 years older than Beena

= (X+9) years

The age of Beena 10 years ago = (X-10) years

The age of Seema after 10 years = (X+9+10) years

=> (X+19) years

According to the given problem

In 10 years Seema will be twice as old as Beena was 10 years ago.

=> X+19 = 2(X-10)

=> X+19 = 2X-20

=> X-2X = -20-19

=> -X = -39

=> X = 39 years

The Present age of Beena = 39 years

The Present age of Seema = X+9 years

=> 39+9 = 48 years

Answer :-

The present ages of Seema and Beena are

48 years and 39 years respectively.

Check:-

The Present age of Beena = 39 years

The Present age of Seema = 48 years

=> 39+9

=> Seema is 9 years older than Beena

and

The age of Beena 10 years ago = 39-10

= 29 years

The age of Seema after 10 years

= 48+10 years

=>58 years

=> 2×29 years

In 10 years Seema will be twice as old as Beena was 10 years ago.

Verified the given relations in the given problem.

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