seema is now 9 years older than beena. in 10 years seema will be twice as old as beena was 10 years ago find their present age
Answers
Step-by-step explanation:
Given :-
Seema is now 9 years older than Beena. in 10 years Seema will be twice as old as Beena was 10 years ago.
To find :-
Find their present age ?
Solution :-
Let the present age of Beena be X years
Then,
The present age of Seema
= 9 years older than Beena
= (X+9) years
The age of Beena 10 years ago = (X-10) years
The age of Seema after 10 years = (X+9+10) years
=> (X+19) years
According to the given problem
In 10 years Seema will be twice as old as Beena was 10 years ago.
=> X+19 = 2(X-10)
=> X+19 = 2X-20
=> X-2X = -20-19
=> -X = -39
=> X = 39 years
The Present age of Beena = 39 years
The Present age of Seema = X+9 years
=> 39+9 = 48 years
Answer :-
The present ages of Seema and Beena are
48 years and 39 years respectively.
Check:-
The Present age of Beena = 39 years
The Present age of Seema = 48 years
=> 39+9
=> Seema is 9 years older than Beena
and
The age of Beena 10 years ago = 39-10
= 29 years
The age of Seema after 10 years
= 48+10 years
=>58 years
=> 2×29 years
In 10 years Seema will be twice as old as Beena was 10 years ago.
Verified the given relations in the given problem.