Question

seema is now 9 years older than beena. in 10 years, seema will be twice as old as beena was 10 years ago. find their present age

Answer 1

HEYA MATE, HERE IS UR ANSWER __________________

Let the age of Seema be x years.

Beena 's age = x-9

After 10 years seema's age =x+10

Before 10 years beena's age =x-9-10

=x-19

According to the question

x+10=2 (x-19)

x+10=2x-38

10+38=2x-x

48=x


Therefore Seema's age =48 years

Beena's age =x-9

=48-9

=39 Years



_______☆☆HOPE THE ANSWER HELPS YOU ☆☆_____☆☆BE BRAINLY ☆☆

Answer 2

Let us assume, the present age of Seema is x years and the present age of Beena is y years.

Given:

x = y + 9

x - y = 9  ------------1

Also given:

x + 10 = 2 (y - 10)

x + 10 = 2y - 20

2y -x = 30 ------------2

Adding equation 1 and equation 2

y = 39 years

Therefore, x = y + 9 = 39 + 9 = 48 years

Answer - The present age of Seema is 48 years and the present age of Beena is 39 years.