Math, asked by adi9390, 1 year ago

Seema is now 9 years older than Beena in 10 years seema will be twice as old as Bina was 10 years ago find their present ages

Answers

Answered by VemugantiRahul
27
Let the present age of beena =x
and present age of seema= x+9

In 10 years(After 10 years)
seema's age= (x+9)+10= (x+19)

10 years ago(Before 10 years)
beena's age= x-10


Given,
seema's age after 10 years= 2( beena's age before 10 years)
=> x+19 = 2(x-10)
=> x+19 = 2x-20
=> x= 39


•°• Present age of Beena x= 39
and present age of seema x+9= 48.


;)
hope it helps
Answered by vkgnabha
8

Answer:

Step-by-step explanation:

Let the present age of Seema be =(X +9)years

Let the present age of Bina be= X years

After 10 yrs,

Age of Seema={(X+9)+10} yrs

Before 10 yrs,

Age of Beena=(X-10) yrs

Therefore age of Seema after 10 yrs= 2(X-10) yrs

A.T.Q

X+19=2(X-10)

X+19=2X-20

X-2X=-19-20

X=39 yrs

Therefore present age of Seema is = 39+9= 48 yrs

Present age of Beena=39 yrs

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