Math, asked by shannubhagat2, 10 months ago

Seema is now 9 years older than Beena. In ten years, Seema will be twice as
old as Beena was 10 years ago. Find their present ages.​

Answers

Answered by MohdAnas11
2

good morning

Step-by-step explanation:

Let beena's present age be x years

Then,Seema's present age will be x + 9 years

Now according to the question:

after 10 years seema will be x + 9 + 10 years old = x + 19 years

and 10 years ago beena was x - 10 years

Therefore x + 19 = 2(x - 10) (Given in the question )

after solving we get :

x = 39 (Beena's present age)

x + 9 = 48 (Seema's present age)

ⓜⓡ.ⓐⓕⓕⓔⓒⓣⓘⓞⓝ

Answered by debdyuti82
4

Answer:

seema age=x

beena age=x+9

after 10 years

seema age=x+10

beena age=x+9+10

10=x+10+x+9+10

10=2x+29

29-10=2x

19=2x

x=19÷2

x=8.5

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