Seema is now 9 years older than Beena ,Seema will be twice as old as Beena was 10 years ago . Find their present age
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Let beena's age = x
seema's age = x+9
in 10 years seema's age will be twice beena's age
x+9+10 = 2x
19 = 2x-x
x = 19
therefore beena is 19 and
seema is 19+9=28
seema's age = x+9
in 10 years seema's age will be twice beena's age
x+9+10 = 2x
19 = 2x-x
x = 19
therefore beena is 19 and
seema is 19+9=28
ankitajaiswal:
i m sorry but answer is wrong
wht
yes, the answer is wrong
wht is the ans
seema age - 48 yrs, Beena age - 39
in which book you ask the question
Mathematics by Mrs Omlata singh and Anju loomba. ....RACHNA SAGAR PVT. LTD
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