seema jogs from one end to the end b of a straight 300m road in 2minutes 50seconds and then turns around and jogs 100m back to point c in a another one minute. what are seema's average speed and velocities in jogging.
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Answered by
2
Answer:
Velocity = dispacement / time
Speed = distance / time
a) when he jogs from A to B on a straight road,
displacement = distance = 300m
time = 2 minutes 30 seconds = 150 s
velocity = 300/150 = 2 m/s
speed = 300/150 = 2m/s
b)when he jogs from A to B and turns back to C,
displacement = 300-100 = 200m
distance = 300+100 = 400m
time = 3 minute 30 second = 210 s
velocity = 200/210 = 20/21 m/s
speed = 400/210 = 40/21 m/s
Answered by
1
Answer:
Given Seema walks
1)300m A to B in 2 min. 50 sec.
2)100m B to C in 1 min.
Total distance travelled = 300+100 = 400 mts.
Total time taken = (60×2) + 50 + (60×1) = 230 sec.
Average Speed = Distance÷Time = 400/230 = 1.7 m/s
Total displacement = 300-100 = 200 m
Average velocity = displacement÷Time = 200/230= 0.86 m/s
Hope it helps u.
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