Question

seema jogs from one end to the end b of a straight 300m road in 2minutes 50seconds and then turns around and jogs 100m back to point c in a another one minute. what are seema's average speed and velocities in jogging.​

Answer 1

Answer:

Velocity = dispacement / time

Speed = distance / time

a) when he jogs from A to B on a straight road,

displacement = distance = 300m

time = 2 minutes 30 seconds = 150 s

velocity = 300/150 = 2 m/s

speed = 300/150 = 2m/s

b)when he jogs from A to B and turns back to C,

displacement = 300-100 = 200m

distance = 300+100 = 400m

time = 3 minute 30 second = 210 s

velocity = 200/210 = 20/21 m/s

speed = 400/210 = 40/21 m/s

Answer 2

Answer:

Given Seema walks

1)300m A to B in 2 min. 50 sec.

2)100m B to C in 1 min.

Total distance travelled = 300+100 = 400 mts.

Total time taken = (60×2) + 50 + (60×1) = 230 sec.

Average Speed = Distance÷Time = 400/230 = 1.7 m/s

Total displacement = 300-100 = 200 m

Average velocity = displacement÷Time = 200/230= 0.86 m/s

Hope it helps u.