Question

Seema makes a saturated solution of ammonium chloride in water at 353 K and leaves the solution to cool at room temperature. What would she observe as the solution cools? Explain.

Answer 1

Answer:

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Explanation:

313 K = × = 62 100 50 31 g g g g. (b) When a saturated solution of potassium chloride at 353 K is cooled, the solubility of potassium chloride in water decreases. As a result, the amount of potassium chloride which exceeds its solubility at lower temperature separates out as crystals.

Answer 2

Explanation:

when a saturated solution of Potassium chloride at 353K is left to cool then solid potassium chloride (or chrystals of potassium chloride will gradually separate out from the solution because the solubility decreases on cooling.