Physics, asked by taniya3857, 1 month ago

seema opens a 4m wide door by minimum force of 5N. what should be the force required if her brother jay tries to open it by pushing at a distance of 2m from the hinge

Answers

Answered by nawaz5396

0

Answer:

10N

Explanation:

The force that is applied is known as TORQUE.

Torque=Radius*force (perpendicular)

case1:- r=4m,F=5N

Torque=20Nm

case2:-r=2m,F=?,Torque will be same to move door=20Nm

F=20/2=10N

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