Question

Seema placed a 20 m ladder against a wall. If the base of the ladder is 12 m from the base of the wall, how high up the wall the ladder reach ?​

Answer 1

Step-by-step explanation:

We can observe that the ladder, wall and base constructs an right angled triangle..

So ladder = hypotenuse = 20

base = base = 12

wall = perpendicular =?

By pythagoras theorem...

H^2 = B^2+P^2

P^2 = 20^2 - 12^2

= 400-144

= 256

P = √256

P= 16 metre

so, height of wall is 16metre

hope it helps you

Answer 2

Answer:

16m high up at the wall the ladder reach

Step-by-step explanation:

Given,

• Ladder placed 20m against the wall which is the hypotenuse
• the ladder is 12m from the base of the wall which is base

The given values make the right-angled triangle.

where,

• base = 12m
• hypotenuse = 20

Now,

According to the Pythagoras theorem,

(height)² + (base)² = (hypotenuse)²

put the values-

(height)² + (12)² = (20)²

(height)² = (20)² - (12)²

(height)² = 400 - 144

(height)² = 256

(height) = √256

(height) = 16m