Question

Seema purchased a new pair of high heeled fashionable shoes. During a picnic

organized by her school Seema intentionally wore these high heeled shoes for showing

off to her classmates. However, Seema could not walk as comfortably as her

classmates during the picnic. After walking through some distance she felt tired. Her

friend Hema held her hand firmly and helped her in walking. Later on, Hema advised

Seema to wear shoes of flat sole on such a trip. Seema

Bought flat shoes and now she felt more comfortable while walking.

a) Why Seema could not walk properly and comfortably during her school picnic?

b) A girl weighing 400N wear high heel shoes. If she stands on one foot only and the

area of heel be 5cm2

, what pressure is acting on the heel?

c) What value was shown by Hema?
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Answer 1

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Answer 2

The answers are as follows:

• Seema was not able to walk properly and comfortably during her school picnic because she was wearing high heeled shoes due to which her complete body weight was distributed over a small area only.
• Given:

Weight of the girl = 400N

Area of the heel = 5 cm²

To find:

Pressure is acting on the heel.

Solution:

We know that Pressure = Force/ Area

= 400/ 5*10⁻⁴

= 8*10⁵ N/m²

Therefore the pressure acting will be 8*10⁵ N/m².

• Hema seems to be a kind hearted girl who is very helpful.