Seema reaches the school early by 10 minutes if she cycles at a speed of 12 km per hour but reaches the school late by 5 minutes if she cycles at 9 km per hour find the distance of the school for her home
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Let us say that the actual distance between Ram's house and school is 'd' km and the ideal time to cover the distance is 't' hours.
When he walks at 5 kmph, he reaches 5 minutes (or 1/12 hours) early
=> d/5 = t - 1/12
=> t = d/5 + 1/12
When he walks at 4 kmph, he reaches 5 minutes (or 1/12 hours) late
=> d/4 = t + 1/12
=> t = d/4 - 1/12
Using the above equations, we can say
d/5 + 1/12 = d/4 - 1/12
=> d/4 - d/5 = 1/12 + 1/12
=> d/20 = 1/6
=> d = 20/6 = 3.33 km
Can u plz refer to this and solve this question.
I have answered another question as same so..
When he walks at 5 kmph, he reaches 5 minutes (or 1/12 hours) early
=> d/5 = t - 1/12
=> t = d/5 + 1/12
When he walks at 4 kmph, he reaches 5 minutes (or 1/12 hours) late
=> d/4 = t + 1/12
=> t = d/4 - 1/12
Using the above equations, we can say
d/5 + 1/12 = d/4 - 1/12
=> d/4 - d/5 = 1/12 + 1/12
=> d/20 = 1/6
=> d = 20/6 = 3.33 km
Can u plz refer to this and solve this question.
I have answered another question as same so..
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