Question

Seema's age is 3 years more than 3 times the age of her daughter. If Seema is 30 years old,find the age of her daughter.

Answer 1

Let present age of Seema be x years and present age of her daughter is y years.

Seema's age is 3 years more than 3 time the age of her daughter.

Seemas age (x) = 3 more (add) than 3 times (multiply) the age of her daughter (y).

According to question,

=> $\sf{x\:=\:3y\:+\:3}$

But wait, in another line we have given that her mother's age i.e. Present age of Seema is 30 years.

Means, we have age of Seema = x = 30

Substitute value of x = 30 in (eq 1), to find the present age of her daughter.

=> $\sf{30\:=\:3y\:+\:3}$

=> $\sf{30\:-\:3\:=\:3y}$

=> $\sf{27\:=\:3y}$

=> $\sf{\frac{27}{3}\:=\:y}$

=> $\sf{9\:=\:y}$

=> $\sf{y\:=\:9}$

•°• Present age of her daughter is 9 years.

Answer 2

Let ,

The daughter's age = x

Then , the present age of seema is (3 + 3x) --- (i)

And also , the present age of seema is 30 --- (ii)

From equation (i) and (ii)

$\to \sf</p><p>3 + 3x = 30 \\ \\ \to \sf</p><p>3x = 27 \\ \\ \to \sf</p><p>x = \frac{27}{3} \\ \\ \to \sf x = 9$

Hence , the present age of her daughter is 9 years