Math, asked by ziyaulislammakandar, 7 months ago

seema's Mother age is 7 times older than her. four years from now, she will be four times as old as seema will then be what are there present ages?​

Answers

Answered by amnaawan10
1

Step-by-step explanation:

Seema's age = x

Age of Seema's mother = 7x

4 years later:

Seema's age = x + 4

Age of Seema's mother = 7x + 4

Since Seema's mother will be 4 times as old as Seema:

4 (x + 4) = 7x + 4

4x + 16 = 7x + 4

12 = 3x

x = 4

Thus Seema is 4 years old while her mother is 28 years old.

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