Seema takes three rounds of a rectangular park measures 30m in length and 25 m inn breadth. Mohit takes 2 rounds of a square shape park measures 50 m each side. Who covers more distance and by how much?
Answers
Answer:
Mohit and by 70m
Step-by-step explanation:
As we all know the perimeter of rectangle is 2*( l + b )
so the perimeter = 2 * 55 =110m
therefore Seema travels 330m
side of square = 50m
therefore perimeter = 4 * 50 = 200m
distance mohit travels = 2 * 200 = 400m
therefore Mohit travels 70m more than Seema
perimeter of rectangular Park = 2(30+25)
= 110
seema takes round = 3 rounds
= 110×3
= 330m
perimeter of square shape Park = 4×50
= 200
mohit takes round = 2 round
= 200×2
= 400m
Mohit covers more distance = 400-330
= 70m
Mohit covers more distance by 70 metre