Seenu have a fruit shop. He is arranged the some set of fruits are column and row wise. Seenu needs to find which row and column has maximum number of fruits. Help him to find out.
INPUT & OUTPUT FORMAT:
Input consists of 2 integers and 1 2D-array. Integers correspond to the size of rows and columns.
SAMPLE INPUT & OUTPUT:
3
3
1 6 8
2 5 1
3 8 2
Sum of rows is 15 8 13
Row 1 has maximum sum
Sum of columns is 6 19 11
Column 2 has maximum sum
Answers
Answer:
#include<iostream>
using namespace std;
int main()
{
int m, n, row, col, sum = 0, row_ind = 0, col_ind = 0;
std::cin >> m >> n;
int row_arr[m];
int i, j;
int mat[m][n];
for(i = 0; i < m; i++)
{
for(j = 0; j < n; j++)
std::cin >> mat[i][j];
}
int z = 0;
for(row=0; row<m; row++)
{
sum = 0;
for(col=0; col<n; col++)
{
sum += mat[row][col];
}
std::cout << sum << "\n";
row_arr[z++] = sum;
}
int temp_row = row_arr[0];
for(i=1;i<m;i++)
{
if(temp_row < row_arr[i])
{
temp_row = row_arr[i];
row_ind = i;
}
}
sum = 0;
int y = 0;
int col_arr[n];
for (i = 0; i < n; ++i)
{
sum = 0;
for (j = 0; j < m; ++j)
{
sum = sum + mat[j][i];
}
col_arr[y++] = sum;
}
int temp_col = col_arr[0];
for(i=1;i<n;i++)
{
if(temp_col < col_arr[i])
{
temp_col = col_arr[i];
col_ind = i;
}
}
return 0;
}
Explanation: All test cases are satisfied
follow me for more answer
Language used : Python Programming
Program :
rows=int(input())
columns=int(input())
l=[]
for i in range(rows):
l.append(sum(list(map(int,input().split(' ')))))
for i in l:
print(i)
Input :
3
3
1 2 3
7 3 1
7 4 1
Output :
6
11
12
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