Question

Sees a bus 1 km aheadof him moving with velocityof 10m/s with what speedthe scooterist should move so as to overtake the bus in 100 s

Answer 1

Distance at the start (t =0 s) of chase

between the two is 1 km or 1000 m.

time for chase is 100 s

velocity of the bus = 10 m/s

distance travelled by the bus before overtake

= v × t =10 × 100 = 1000 m

So, the total distance needed to be covered

in given 100 s by the scooterist to overtake the

bus = 1000 m + 1000 m = 2000 m

time = 100 s

so, velocity required = d / t

= 2000/ 100 = 20 m/s

Answer 2

$\huge\mathfrak\blue{Answer:-}$

Given:

t = 100s,

s = 1000m;

v = 10m/s.

But this is the relative speed with respect to the bus

To Find:

speed of the scooterist so that he should move so as to overtake the bus in 100 s.

Solution:

Vs - actual velocity of speed of the the scooterist so that he should move so as to overtake the bus in 100 s;

Vb = velocity of bus;

v = relative velocity of scooter with respect to bus.

v = Vs-Vb as both busand scooter are moving in same direction.

10 = Vs-10;

10 + 10 = vs

20 = vs

So,

Vs = 20m/s