Question

Seeta and Rashmi have chocolate in the ratio 3:2.if seeta gives 2 chocolate to rashmi,both of them will have equal number of chocolates.how many chocolates did seeta have initially?

Answer 1

Seeta. Rashmi
3x. 2x
3x- 2. 2x+2
A/c to que.
3x-2 = 2x+2
X= 4
Now Seeta have. 3*4 = 12
Rashmi has 2*4 = 8

Answer 2

Number of chocolates seeta had initially = 12

Given :

• Seeta and Rashmi have chocolate in the ratio 3 : 2

• If Seeta gives 2 chocolate to Rashmi , both of them will have equal number of chocolates

To find :

The number of chocolates Seeta had initially

Solution :

Step 1 of 2 :

Form the equation

Here it is given that Seeta and Rashmi have chocolate in the ratio 3 : 2

Let the number of chocolates Seeta and Rashmi had 3x and 2x respectively

If Seeta gives 2 chocolate to Rashmi , both of them will have equal number of chocolates

Then ,

Number of chocolates of Seeta = 3x - 2

Number of chocolates of Rashmi = 2x + 2

By the given condition

3x - 2 = 2x + 2

Step 2 of 2 :

Find number of chocolates Seeta had initially

3x - 2 = 2x + 2

⇒ 3x - 2x = 2 + 2

⇒ x = 4

Initially number of chocolates of Seeta = 3 × 4 = 12

Initially number of chocolates of Rashmi = 2 × 4 = 8

Hence number of chocolates Seeta had initially is 12

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