Question

Seeta rides her bicycle to school. in morning while going to school she averages a speed of 15km/h. On her return from school at evening along the same route she averages a speed of 12 km/h calculate the average speed of seeta's trip​

Answer 1

$avg. \: speed \: = \frac{total \: distance \: covered}{total \: time \: taken}$

$d_{1} = 15km \\ d_{2} = 12km \\ \\ t_{1} = 1hour \\ t_{2} = 1hour \\ \\ avg. \: speed \: = \frac{ d_{1} + d_{2} } { t_{1} + t_{2} } \\ = \frac{15km + 12km}{1hour \: + 1hour} \\ = \frac{27km}{2hour} \\ = \frac{27}{2} \times \frac{5}{18} = 3.75m/s$

Answer 2

Explanation:

Check out the given attachment ⬆️

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