Question

Seg AB is parallel to x-axis and co-ordinate of point A are (1,3), then co-ordinate of point B can be ____?

(3,1)

(5,3)

(3,0)

(1.-3

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Answer 1

Answer:

S same it is correct i think

Answer 2

The co-ordinate of point B can be (5,3)

Given :

Seg AB is parallel to x-axis and co-ordinate of point A are (1,3)

To find :

The co-ordinate of point B can be

(3,1)

(5,3)

(3,0)

(1, -3)

Solution :

Step 1 of 2 :

Find the equation of the Seg AB

The equation of x axis is y = 0

Since the Seg AB is parallel to x-axis

Let the equation of the Seg AB be

y = k - - - - - (1)

Now the co-ordinate of point A are (1,3)

So the equation y = k passes through the point (1,3)

∴ k = 3

So the equation of the Seg AB is y = 3

Step 2 of 2 :

Find the possible co-ordinate of point B

Since the equation of the Seg AB is y = 3

So the ordinate of any on the Seg AB is 3

For (3,1) the ordinate is 1

So (3,1) can not be the coordinate of the point B

For (5,3) the ordinate is 3

So (5,3) can be the coordinate of the point B

For (3,0) the ordinate is 0

So (3,0) can not be the coordinate of the point B

For (1, -3) the ordinate is - 3

So (1, -3) can not be the coordinate of the point B

So the possible co-ordinate of point B is (5,3)

Hence the correct option is (5,3)

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