Question

seg AB is the diameter of a circle.C is the point on the circumference such a that in triangle ABC,angle B is less than by 10 find the measure of all angles of triangleABC

Answer 1

Answer:

ANSWER

Angle subtended by diameter on any point on circle is 90

o

⇒∠ACB=90

o

In △ABC,∠B+∠C+90=180

⇒∠A−10+∠A+90=180⇒∠A=50

o

⇒∠B=40

o

Answer 2

Answer:

x2+5x+6=(x+2)(x+3)

If the numerator is of same or higher degree than the denominator, one has to get the quotient before applying partial fractions. It is not necessary to find out the remainder.Here the quotient is 2.

2x2+3x2+5x+6=2+Ax+2+Bx+3(1)

Multiplying by (x+2)(x+3)

2x2+3=2((x+2)(x+3)+A(x+3)+B(x+2)(2)

Plug in x=−2

A=11

Plug in x=−3

B=−21

Now you can integrate (1)