Question

seg AD is a median of ∆ABC. If AB =12, AD=10, AC = 16 then find BC

Answer 1

solution :

In ∆ABC ,

AB = 12 , AC = 16 ,

median ( AD ) = 10 ,

BC = ?

By , Appolonius Theorem ,

2( BC² + AD² ) = AB² + AC²

=> BC² + 10² = ( 12² + 16² )/2

=> BC² + 100 = ( 144 + 256 )/2

=> BC² + 100 = 400/2

=> BC² = 200 - 100

=> BC² = 100

=> BC = 10

•••••

Answer 2

please marke as brinalist.

I hope this answer is help you..