seg AD is a median of ∆ABC.lf AB=12,AD=10,AC=16 then find BC
shashidhar739:
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Solution -
In ∆ABC,
AB=12,AC=16,
Median (AD) =10,
BC=?
By, appolonius theorem,
2(BC²+AD²) =AB²+AC²
BC²+10²=(12²+16²) /2
BC²+100=(144+256)/2
BC²+100=400/2
BC²=200-100
BC²=100
Bc=10
In ∆ABC,
AB=12,AC=16,
Median (AD) =10,
BC=?
By, appolonius theorem,
2(BC²+AD²) =AB²+AC²
BC²+10²=(12²+16²) /2
BC²+100=(144+256)/2
BC²+100=400/2
BC²=200-100
BC²=100
Bc=10
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