Question

seg AD is a median of ∆ABC.lf AB=12,AD=10,AC=16 then find BC

Answer 1

Solution -
In ∆ABC,

AB=12,AC=16,

Median (AD) =10,

BC=?

By, appolonius theorem,

2(BC²+AD²) =AB²+AC²

BC²+10²=(12²+16²) /2

BC²+100=(144+256)/2

BC²+100=400/2

BC²=200-100

BC²=100

Bc=10