Question

Seg PM is a median of ∆PQR if PQ=11cm,PR=17 and QR=12cm then find PM?​

Answer 1

Answer:

13cm

Step-by-step explanation:

formula:   $m=\sqrt{\frac{2b^{2}+2c^{2}-a^{2} }{4} }$

PM = m

PR = b = 17

PQ = c = 11

RQ = a = 12

therefore, PM = 13cm