Question

Seg PS ┴ ray RQ, seg QT ┴ seg PR.

If QR = 6, PS = 6, PR = 12, find QT​

Answer 1

Answer:

for you to be layed down the street

Answer 2

Given : Seg PS ┴ ray RQ, seg QT ┴ seg PR.

QR = 6, PS = 6, PR = 12,

To Find : QT

Solution:

Area of Δ = (1/2) * base * height

Area of Δ PQR

Base PR  and height QT

= (1/2) * PR * QT

Base RQ  and height  PS

= (1/2) * RQ * PS

Equate Area

(1/2) * PR * QT = (1/2) * RQ * PS

=> PR * QT = RQ * PS

PR = 12

QT = ?

RQ = PS = 6

=> 12 * QT  = 6 * 6

=> QT  = 3

Learn More :

Ratio of area of 2 similar triangles are 2:3. Area of the larger triangle is

brainly.in/question/7877543

if triangle abc- triangle def area of triangle abc is 64 square ...

brainly.in/question/14594418