Question

segment ad is the median to the side bc of a right triangle abc right angled at c prove that 4ad^2 = 4ac^2 + bc^2.....PLS HELP

Answer 1

Answer:

Given: triangle ABC is a right angled triangle. CD=DB.

To prove: triangle AD^2=4AC^2+BC^2

Proof:

triangle ACD

AD^2=AC^2+DC^2

AD^2=AC^2+(BC)^2 by 2

AD^2=AC^2+BC^2 by 4

AD^2=4AC^2+BC^2 by 4

4AD^2=4AC^2+BC^2