segment bc of length 4 metre is divided into two parts such that BD square is equal to DC into BC find the length ofDc
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DC=6−2
5
m
Step-by-step explanation:
Given:
BC = 4 m
Let BD = x
Then DC=4-x
BD^2=DC*BCBD
2
=DC∗BC
\implies\:x^2=(4-x)*4⟹x
2
=(4−x)∗4
\implies\:x^2=16-4x⟹x
2
=16−4x
\implies\:x^2+4x-16=0⟹x
2
+4x−16=0
To find x, we solve this equation
\implies\:x^2+4x-16=0⟹x
2
+4x−16=0
x^2+4x=16x
2
+4x=16
x^2+4x+4=16+4x
2
+4x+4=16+4
(x+2)^2=20(x+2)
2
=20
x+2=x+2= ±2\sqrt52
5
x=-2x=−2 ±2\sqrt52
5
But x cannot be negative
x=-2+2\sqrt5x=−2+2
5
x=2\sqrt5-2x=2
5
−2
Now,
DC=4-(2\sqrt5-2)DC=4−(2
5
−2)
DC=4-2\sqrt5+2DC=4−2
5
+2
DC=6-2\sqrt5\:mDC=6−2
5
m
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