Math, asked by manishanikam522, 6 months ago

segment with the positiv
direction of x-axis is 30°
[NCERT EXEMPLAR
3. Find the equation of the line whose perpendicular distance from the origin is 4 units an
the angle which the normal makes with the positive direction of x-axis is 15° INCERT
Find the​

Answers

Answered by bs329559
0

Answer:

Use normal form, xCosα+ySinα=p⟹(1)

p=4 and α=15⁰

Cos15⁰=Cos(45⁰−30⁰)

=Cos45⁰Cos30⁰+Sin45⁰Sin30⁰

=

2

1

2

3

+

2

1

2

1

=

2

2

3+1

Sin15⁰=

[1−Cos²15⁰]

=

2(

2

)

2

1−(

3+1

=

8

(1−(3+1+2)

3

=

8

(8−4−2)

3

=

8

(4−2)

3

=

2

2

(4−2)

3

put Sin15⁰,Cos15⁰,p=4 in equation (1)

x[Cos15]+y[Sin15]=4

x[(

3+1

)]+y[4−2

3

]=4∗2

2

x[(

3+1

)]+y[4−2

3

]=8

2

Step-by-step explanation:

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