Question

sehaj batra gets pocket money from his father everyday. Out of the pocket money, he save money for poor people in locality.On first day he saves rupees 27.5.On each succeeding day he increases his savings by rupees 2.5. Find the amount of money saved by sehaj on 10th day. The amount saved by Sehaj on 25th day and the amount saved by the sehaj in 30 days.​

Answer 1

Answer:

350 ,960,1020 is the t money saved

Answer 2

Answer:-

i. Money saved on 1st day = Rs. 27.5

Sehaj increases his saving by a fixed amount of Rs. 2.5 .'. His saving form an AP with a = 27.5 , d = 2.5 n= 10 a10=?

a+(n-1)d

To Find 10th term

a10= 27.5+(10-1)2.5

a10=27.5+22.5

a10=50

Money saved on 10th day,

Rs. 50

ii. a25 = a = 27.5 , n= 25 & d= 2.5

an = a+(n-1)d

a25 = 27.5+ (25-1)(2.5)

a25 = 27.5 24(2.5)

a25 = 27.5 + 60 = Rs. 87.5

iii. Total amount saved by Sehaj in 30 days. 302 x 27.5+ (30- 1) × 2.5]

=

= 15(55+29(2.5)

= Rs. 1912.5